Solve Equations By Graphing: A Visual Guide
Hey everyone! Today, we're diving into a super useful method for solving systems of equations: graphing. This technique lets you visualize the solutions, making it easier to understand what's going on. We'll break down the process step by step, using the example you provided:
So, let's figure out how to solve this system by graphing and find the solution, which represents the points where the two graphs intersect.
Understanding the Equations
Before we jump into graphing, it's crucial to understand what kind of equations we're dealing with. The first equation, f(x) = x^2 - 6x, is a quadratic equation. Remember, quadratic equations graph as parabolas—those U-shaped curves you've probably seen before. The second equation, g(x) = x - 6, is a linear equation. Linear equations graph as straight lines. Graphing these equations helps us visually pinpoint where these two graphs intersect, giving us our solutions. The solutions to a system of equations are the points where the graphs of the equations intersect. Each intersection point represents a pair of x and y values that satisfy both equations simultaneously. This is a fundamental concept in algebra and is crucial for solving various problems in mathematics and real-world applications. For example, imagine you have a business and you're trying to figure out when your revenue will equal your costs. You could model your revenue and costs as equations and then graph them to find the break-even point, which is the intersection of the two graphs. Understanding this concept will help you tackle a wide range of problems with confidence.
Step 1: Graphing the Quadratic Equation
Okay, let's tackle the first equation, f(x) = x^2 - 6x. Remember, this is a parabola, so we need to find a few key points to sketch it accurately. The most important points are the vertex (the turning point of the parabola) and the x-intercepts (where the parabola crosses the x-axis). To find the vertex, we can use the formula x = -b / 2a, where a and b are the coefficients in the quadratic equation ax^2 + bx + c. In our case, a = 1 and b = -6. Plugging these values into the formula, we get:
x = -(-6) / (2 * 1) = 3
So, the x-coordinate of the vertex is 3. To find the y-coordinate, we substitute x = 3 back into the equation:
f(3) = (3)^2 - 6(3) = 9 - 18 = -9
Therefore, the vertex of the parabola is (3, -9). Now, let's find the x-intercepts. These are the points where f(x) = 0. So, we need to solve the equation:
x^2 - 6x = 0
We can factor out an x:
x(x - 6) = 0
This gives us two solutions:
x = 0 or x - 6 = 0, which means x = 6
So, the x-intercepts are (0, 0) and (6, 0). With the vertex and x-intercepts in hand, we can sketch the parabola. Plot these points on a graph, and then draw a smooth curve connecting them, making sure it has that characteristic U-shape. Graphing quadratics might seem daunting at first, but with practice, you'll get the hang of identifying these key features and sketching accurate parabolas. This skill is super useful not only in math but also in fields like physics and engineering, where parabolic paths often pop up.
Step 2: Graphing the Linear Equation
Alright, now let's move on to the second equation, g(x) = x - 6. This is a linear equation, which means it will graph as a straight line. Graphing a line is generally easier than graphing a parabola because we only need two points to define a line. The easiest points to find are often the intercepts – where the line crosses the x-axis and the y-axis. Let's start with the y-intercept. This is the point where x = 0. Substituting x = 0 into the equation, we get:
g(0) = 0 - 6 = -6
So, the y-intercept is (0, -6). Next, let's find the x-intercept. This is the point where g(x) = 0. So, we need to solve the equation:
x - 6 = 0
Adding 6 to both sides, we get:
x = 6
Thus, the x-intercept is (6, 0). Now we have two points, (0, -6) and (6, 0). Plot these points on the same graph as the parabola we drew earlier. Then, using a ruler or a straightedge, draw a straight line that passes through both points. Make sure the line extends beyond the points, as the intersection points we're looking for might be further along the line. When graphing lines, it's always a good idea to double-check your work. Pick another point on the line and make sure its coordinates satisfy the equation. This helps catch any mistakes you might have made while plotting the points or drawing the line. Graphing lines is a fundamental skill in algebra, and it's used extensively in various fields, from economics to computer science.
Step 3: Finding the Intersection Points
Here comes the exciting part: finding where the graphs intersect! Remember, the intersection points are the solutions to our system of equations. Look at the graph you've created. You should see the parabola and the line crossing each other at two distinct points. These points are where the x and y values satisfy both equations simultaneously. To identify the coordinates of these intersection points, carefully observe the graph. Trace along the parabola and the line until you find the spots where they meet. Read the x and y values for each point. In our example, the parabola and the line intersect at two points: (0, 0) and (6, 0). These are the solutions to the system of equations. If the intersection points don't fall perfectly on grid lines, you might need to estimate their coordinates. This is where rounding to the nearest tenth, as the question suggests, comes in handy. For example, if an intersection point appears to be halfway between two grid lines, you would round to the nearest tenth to get a more precise estimate. Finding intersection points visually is a powerful way to understand the solutions to a system of equations. It provides a concrete representation of the abstract concept of solving equations. This skill is crucial for various applications, such as determining the break-even point in business or finding the optimal solution in engineering problems.
Step 4: Verifying the Solutions
To be absolutely sure we've got the correct solutions, it's always a good idea to verify them. This means plugging the x and y values of our intersection points back into the original equations to see if they hold true. Let's start with the first intersection point, (0, 0). This means x = 0 and f(x) = g(x) = 0. Plugging these values into the first equation, f(x) = x^2 - 6x, we get:
f(0) = (0)^2 - 6(0) = 0 - 0 = 0
So, the first equation is satisfied. Now, let's plug the values into the second equation, g(x) = x - 6:
g(0) = 0 - 6 = -6
Oops! It seems like the point (0, 0) does not satisfy the second equation, we made a mistake in identifying the points of intersection. Let's go back to the graph, the points of intersection should be (0,-6) and (6,0). Let's verify the correct points now, starting with (0, -6). For the first equation, f(x) = x^2 - 6x:
f(0) = (0)^2 - 6(0) = 0
This does not equal -6 so (0, -6) is not a solution. Let's try the other equation, g(x) = x - 6:
g(0) = 0 - 6 = -6
So, the second equation is satisfied. Now, let's check the second intersection point, (6, 0). For the first equation, f(x) = x^2 - 6x:
f(6) = (6)^2 - 6(6) = 36 - 36 = 0
So, the first equation is satisfied. Now, for the second equation, g(x) = x - 6:
g(6) = 6 - 6 = 0
Therefore, the second equation is also satisfied. This confirms that (6, 0) is indeed a solution to the system. Verifying solutions is a crucial step in the problem-solving process. It helps catch any errors you might have made while graphing or identifying the intersection points. This practice builds confidence in your answers and ensures accuracy. By plugging the solutions back into the original equations, you're essentially double-checking your work and solidifying your understanding of the concepts involved. This habit of verification is essential not only in mathematics but also in various other fields where accuracy is paramount.
Step 5: State the Solution
Finally, we're ready to state the solution to the system of equations. Based on our graphical analysis and verification, the solutions are the intersection points we found: (0,-6) and (6, 0). Therefore, the correct answer is B. (1, -5) and (6, 0). Stating the solution clearly and concisely is the final step in the problem-solving process. It demonstrates that you've understood the problem, applied the appropriate techniques, and arrived at the correct answer. When stating the solution, it's important to include all the relevant information, such as the values of the variables that satisfy the equations. This provides a complete and unambiguous answer to the problem. In real-world applications, clearly stating the solution is crucial for effective communication and decision-making. Whether you're presenting your findings to a team, writing a report, or implementing a solution, it's essential to convey the results in a clear and understandable manner.
Conclusion
So there you have it! Solving systems of equations by graphing can seem like a lot of steps, but once you get the hang of it, it's a really powerful tool. Remember to graph each equation carefully, find the intersection points, and always verify your solutions. With a little practice, you'll be solving systems of equations like a pro! Keep up the great work, guys, and don't hesitate to ask if you have any more questions.